var_c vs var_e
FLAGGEDProblem: two-sum
A→B100%B→A100%Shared fingerprints54
136tokens in the longest matched region
var_c
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n; long long t;
cin >> n >> t;
unordered_map<long long, int> seen;
seen.reserve(2 * n);
int idx = 1;
while (idx <= n) {
long long x;
cin >> x;
long long need = t - x;
auto it = seen.find(need);
if (seen.end() != it) {
cout << it->second << ' ' << idx << '\n';
return 0;
}
seen[x] = idx;
idx = idx + 1;
}
return 0;
}
var_e
#include <bits/stdc++.h>
using namespace std;
// two-sum, hash map approach, O(n) expected
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int total; // element count
long long goal; // required sum
cin >> total >> goal;
unordered_map<long long, int> prior; // value -> earliest index
prior.reserve(2 * total);
int pos = 1;
while (pos <= total) {
long long cur;
cin >> cur; // next value
long long complement = goal - cur;
auto hit = prior.find(complement);
if (prior.end() != hit) {
// found the partner we stored earlier
cout << hit->second << ' ' << pos << '\n';
return 0;
}
prior[cur] = pos; // stash for later
pos = pos + 1;
}
return 0;
}