var_a vs var_e
FLAGGEDProblem: two-sum
A→B48%B→A37%Shared fingerprints20
49tokens in the longest matched region
var_a
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int cnt; long long goal;
cin >> cnt >> goal;
unordered_map<long long, int> encountered;
encountered.reserve(cnt * 2);
for (int cursor = 1; cursor <= cnt; cursor++) {
long long val;
cin >> val;
auto found = encountered.find(goal - val);
if (found != encountered.end()) {
cout << found->second << ' ' << cursor << '\n';
return 0;
}
encountered[val] = cursor;
}
return 0;
}
var_e
#include <bits/stdc++.h>
using namespace std;
// two-sum, hash map approach, O(n) expected
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int total; // element count
long long goal; // required sum
cin >> total >> goal;
unordered_map<long long, int> prior; // value -> earliest index
prior.reserve(2 * total);
int pos = 1;
while (pos <= total) {
long long cur;
cin >> cur; // next value
long long complement = goal - cur;
auto hit = prior.find(complement);
if (prior.end() != hit) {
// found the partner we stored earlier
cout << hit->second << ' ' << pos << '\n';
return 0;
}
prior[cur] = pos; // stash for later
pos = pos + 1;
}
return 0;
}